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請教老師函數(shù) [文華財(cái)經(jīng)]

  • 咨詢內(nèi)容: G:=MA(C,5);D1:=MA(C,10);NNH:=BARSLAST(H=HHV(H,7)) ,NODRAW;NNL:=BARSLAST(L=LLV(L,7)) ,NODRAW;NN:=IF(REF(G,NNH)>REF(D1,NNH) AND NNH<=4,NNH,IF(REF(G,NNL)<REF(D1,NNL) AND NNL<=4,NNL,5)) ,NODRAW;N:=IF(ISLASTBAR AND NN>0,NN,5) ,NODRAW;HH:=REF(H,N)=HHV(H,6);LL:=REF(L,N)=LLV(L,6);FG01:BACKSET(HH,N+1)>BACKSET(HH,N),NODRAW;FD01:BACKSET(LL,N+1)>BACKSET(LL,N) ,NODRAW;FG02:=FG01=FD01 AND G>D1,NODRAW;FD02:FG01=FD01 AND G<D1,NODRAW;TTTT:BARSLAST(FD01),NODRAW;FG0:=FG01 AND IF(FG02=1,H=HHV(H,BARSLAST(REF(FD01,1))+1),H=HHV(H,IF(BARSLAST(L=LLV(L,7))>=5,5,BARSLAST(FD01)))) AND FD02=0 ,NODRAW;FD0:=FD01 AND IF(FD02=1,L=LLV(L,BARSLAST(REF(FG01,1))+1),L=LLV(L,IF(BARSLAST(H=HHV(L,7))>=5,5,BARSLAST(FG01))))? AND FG02=0 ,NODRAW;GT:BARSLAST(FG0),NODRAW;DT:BARSLAST(FD0),NODRAW;LLLL:DT=0 AND REF(DT,1)<GT AND L>REF(L,REF(DT,1)+1),NODRAW;FG1:BACKSET(REFX(GT,1)=0 AND GT<DT AND REFX(H,1)>=REF(H,GT),GT+1),NODRAW;FD1:BACKSET(REFX(DT,1)=0 AND DT<GT AND REFX(L,1)<=REF(L,DT),DT+1),NODRAW;FG11:=IF(GT=0 AND REF(GT,1)<DT AND IF(REF(G,BARSLAST(L=LLV(L,7)))>REF(D1,BARSLAST(L=LLV(L,7))),BARSLAST(L=LLV(L,7))<5,1) AND? H<REF(H,REF(GT,1)+1),1,0),NODRAW;FD11:=IF(DT=0 AND REF(DT,1)<GT AND IF(REF(G,BARSLAST(H=HHV(H,7)))<REF(D1,BARSLAST(H=HHV(H,7))),BARSLAST(H=HHV(H,7))<5,1) AND L>REF(L,REF(DT,1)+1),1,0),NODRAW;GT1:BARSLAST(FG11<>1 AND FG1<>1 AND FG0),NODRAW;DT1:BARSLAST(FD11<>1 AND FD1<>1 AND FD0),NODRAW;FD2:BACKSET(REFX(GT1,1)=0 AND DT1<3 AND GT1-DT1<4 AND REF(L,DT1)>LLV(L,GT1+5),DT1+1),NODRAW;FG2A:BACKSET(REFX(GT1,1)=0 AND DT1<3 AND GT1-DT1<4 AND REF(L,DT1)<=LLV(L,GT1+5) AND REF(H,GT1)>HHV(H,GT1+5),GT1+1),NODRAW;FG2B:=IF(GT1=0 AND DT1<4 AND REF(GT1,1)-DT1<4 AND REF(L,DT1)<=LLV(L,REF(GT1,1)+6) AND H>HHV(H,REF(GT1,1)+6),1,0),NODRAW;FG2:BACKSET(REFX(DT1,1)=0 AND GT1<3 AND DT1-GT1<4 AND REF(H,GT1)<HHV(H,DT1+5),GT1+1),NODRAW;FD2A:BACKSET(REFX(DT1,1)=0 AND GT1<3 AND DT1-GT1<4 AND REF(H,GT1)>=HHV(L,DT1+5) AND REF(L,DT1)>LLV(L,DT1+5),DT1+1),NODRAW;FD2B:=IF(DT1=0 AND GT1<4 AND REF(DT1,1)-GT1<4 AND REF(H,GT1)>=HHV(H,REF(DT1,1)+6) AND L>LLV(L,REF(DT1,1)+6),1,0),NODRAW;TTTTTT: H<REF(H,REF(GT1,1)+1) AND DT1<4,NODRAW;HHHHHH:REF(LLV(L,10),DT1),NODRAW;FG21:IF(GT1=0 AND DT1<4 AND H<=REF(H,REF(GT1,1)+1)? ,1,0),NODRAW;FD21:IF(DT1=0 AND GT1<4? AND L>=REF(L,REF(DT1,1)+1) ,1,0),NODRAW;FD231:BACKSET(REFX(GT1,1)=0 AND DT1>3 AND GT1>DT1 AND GT1-DT1<4 AND REFX(H,1)>REF(H,GT1) AND REF(L,DT1)>REF(LLV(L,10),DT1),DT1+1),NODRAW;FG23:BACKSET(REFX(GT1,1)=0 AND DT1>3 AND GT1>DT1 AND? GT1-DT1<4 AND REFX(H,1)>REF(H,GT1) AND (REF(H,GT1)<REF(HHV(H,13),GT1) OR REF(FD231,DT1)=0),GT1+1),NODRAW;FG231:BACKSET(REFX(DT1,1)=0 AND GT1>3? AND DT1>GT1 AND DT1-GT1<4 AND REFX(L,1)<REF(L,DT1) AND REF(H,GT1)<REF(HHV(H,10),GT1) ,GT1+1),NODRAW;FD23:BACKSET(REFX(DT1,1)=0 AND GT1>3? AND DT1>GT1 AND DT1-GT1<4 AND REFX(L,1)<REF(L,DT1) AND ( REF(L,DT1)>REF(LLV(L,13),DT1) OR REF(FG231,GT1)=0),DT1+1),NODRAW;FDD23:REF(H,GT1)<REF(HHV(H,10),GT1) OR REF(FD23,DT1)=0,NODRAW;FD24:BACKSET(REFX(GT1,1)=0 AND DT1>3 AND GT1>DT1 AND GT1-DT1<4 AND REFX(H,1)<HHV(H,GT1+3) AND REF(L,DT1)>LLV(L,DT1+5),DT1+1),NODRAW;FG24:BACKSET(REFX(DT1,1)=0 AND GT1>3? AND DT1>GT1 AND DT1-GT1<4 AND REFX(L,1)>LLV(L,DT1+3) AND REF(H,GT1)<HHV(H,GT1+5),GT1+1),NODRAW;GT2:BARSLAST(FG21<>1 AND FG23<>1 AND FG231<>1 AND FG24<>1? ?AND FG2<>1 AND FG2A<>1 AND FG2B<>1 AND GT1=0),NODRAW;DT2:BARSLAST(FD21<>1 AND FD23<>1 AND FD231<>1 AND FD24<>1? AND FD2<>1 AND FD2A<>1 AND FD2B<>1 AND DT1=0),NODRAW;FG3:BACKSET(REFX(GT2,1)=0 AND GT2<DT2 AND REFX(H,1)>=REF(H,GT2),GT2+1),NODRAW;FD3:BACKSET(REFX(DT2,1)=0 AND DT2<GT2 AND REFX(L,1)<=REF(L,DT2),DT2+1),NODRAW;FG31:IF(GT2=0 AND REF(GT2,1)<DT2 AND H<REF(H,REF(GT2,1)+1),1,0),NODRAW;FD31:IF(DT2=0 AND REF(DT2,1)<GT2 AND L>REF(L,REF(DT2,1)+1),1,0),NODRAW;GT3:BARSLAST(GT2=0 AND FG3<>1 AND FG31<>1 ),NODRAW;DT3:BARSLAST(DT2=0 AND? FD3<>1 AND FD31<>1),NODRAW;FG4:BACKSET(REFX(GT3,1)=0 AND GT3<DT3 AND REFX(H,1)>=REF(H,GT3),GT3+2),NODRAW;FD4:BACKSET(REFX(DT3,1)=0 AND DT3<GT3 AND REFX(L,1)<=REF(L,DT3),DT3+3),NODRAW;FG41:IF(GT3=0 AND REF(GT3,1)<DT3 AND H<REF(H,REF(GT3,1)+1),1,0),NODRAW;FD41:IF(DT3=0 AND REF(DT3,1)<GT3 AND L>REF(L,REF(DT3,1)+1),1,0),NODRAW;HHH:=GT3=0 AND FG31<>1 AND? FG3<>1,NODRAW;LLL:=DT3=0 AND FD31<>1 AND? FD3<>1,NODRAW;DRAWTEXT(LLL,L,'',FONTSIZE25,COLORRED,VALIGN0;DRAWTEXT(HHH,H,'',FONTSIZE25,COLORGREEN;
    未來函數(shù)可以用?替換嗎

    ?

    ?來源:程序化99

  • 文華技術(shù)人員: ?BACKSET 未來函數(shù)不能用非未來函數(shù)替換的 您了解下

    ?

    ?來源: m.weiqiv.net.cn

  • 文華客服: ?好的,謝謝

    ?

  • 網(wǎng)友回復(fù): ?老師 未來函數(shù) 是不是數(shù)據(jù)比較滯后。

    ?

  • 網(wǎng)友回復(fù): ?未來函數(shù)主要影響是 未來的數(shù)據(jù)會(huì)影響過去的變量的計(jì)算
    也就是在標(biāo)記 畫線的時(shí)候 位置會(huì)受到新的數(shù)據(jù)影響而變化? 您了解下

 

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