咨詢內容：

麻煩老師改成新版博易大師 的

AS:=(C*3+O+H+L)/6;
XJ:=(AS+0.618*REF(AS,1)+0.382*REF(AS,2)+0.236*REF(AS,3)+0.146*REF(AS,4))/2.382;
{回調認同}
HLX:=EMA(HHV(XJ,3),15);
LLX:=EMA(LLV(XJ,3),15);
CH:=CROSS(XJ,HLX);CL:=CROSS(LLX,XJ);
CHH:=BARSLAST(CH);CLL:=BARSLAST(CL);
YF1:=(CHH<CLL?OR?CH)?AND?NOT(CL);
YF2:=(CHH>CLL?OR?CL)?AND?NOT(CH);
TF:=IF(YF1,LLX,HLX);
TFB:=(HLX+LLX)/2;
XJK:=SMA(EMA(XJ,3),3,1);
ZWSH:=(HHV(XJ,2)+HHV(XJ,3)+HHV(XJ,4)+HHV(XJ,5))/4;
SH:=EMA(ZWSH,21);
ZWSL:=(LLV(XJ,2)+LLV(XJ,3)+LLV(XJ,4)+LLV(XJ,5))/4;
SL:=EMA(ZWSL,21);
SCH:=CROSS(XJ,SH);
SCL:=CROSS(SL,XJ);
SHH:=BARSLAST(SCH);
SLL:=BARSLAST(SCL);
SF1:=(SHH<SLL?OR?SCH)?AND?NOT(SCL);
SF2:=(SHH>SLL?OR?SCL)?AND?NOT(SCH);
TFS:=IF(SF1,SL,SH);
TFBS:=(SL+SH)/2;
{K線}
KX1:=(CLOSE>=OPEN)?AND?XJ>=TFS;
KX2:=(CLOSE<OPEN)?AND?XJ>=TFS;
KX3:=(CLOSE>=OPEN)?AND?XJ<TFS;
KX4:=(CLOSE<OPEN)?AND?XJ<TFS;
KX5:=((XJ>=TFS?AND?XJ<TF)OR?(XJ<TFS?AND?XJ>=TF))?AND?CLOSE>=OPEN;
KX6:=((XJ>=TFS?AND?XJ<TF)OR?(XJ<TFS?AND?XJ>=TF))?AND?CLOSE<OPEN;

{K線}
STICKLINE(KX1,C,O,4,1),COLOR4440FF;
STICKLINE(KX1,C,H,0.5,1),COLOR4440FF;
STICKLINE(KX1,O,L,0.5,1),COLOR4440FF;
STICKLINE(KX2,C,O,4,0),COLOR4440FF;
STICKLINE(KX2,O,H,0.5,0),COLOR4440FF;
STICKLINE(KX2,C,L,0.5,0),COLOR4440FF;
STICKLINE(KX3,C,O,4,1),COLORFFFF33;
STICKLINE(KX3,C,H,0.5,1),COLORFFFF33;
STICKLINE(KX3,O,L,0.5,1),COLORFFFF33;
STICKLINE(KX4,C,O,4,0),COLORFFFF33;
STICKLINE(KX4,O,H,0.5,0),COLORFFFF33;
STICKLINE(KX4,C,L,0.5,0),COLORFFFF33;
{STICKLINE(KX5,C,O,4,1),COLOR5E5E5E;
STICKLINE(KX5,C,H,0.5,1),COLOR5E5E5E;
STICKLINE(KX5,O,L,0.5,1),COLOR5E5E5E;
STICKLINE(KX6,C,O,4,0),COLOR5E5E5E;
STICKLINE(KX6,O,H,0.5,0),COLOR5E5E5E;

?

?來源:程序化99網（ m.weiqiv.net.cn ）

博易技術人員： 您好，以上公式可以編譯通過使用，請問是什么問題？ 來源 程序化久久網